3x^2-5x-216=0

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Solution for 3x^2-5x-216=0 equation:



3x^2-5x-216=0
a = 3; b = -5; c = -216;
Δ = b2-4ac
Δ = -52-4·3·(-216)
Δ = 2617
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{2617}}{2*3}=\frac{5-\sqrt{2617}}{6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{2617}}{2*3}=\frac{5+\sqrt{2617}}{6} $

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